28^2+x^2=56^2

Solution for 28^2+x^2=56^2 equation:

28^2+x^2=56^2

We move all terms to the left:

28^2+x^2-(56^2)=0

We add all the numbers together, and all the variables

x^2-2352=0

a = 1; b = 0; c = -2352;
Δ = b2-4ac
Δ = 02-4·1·(-2352)
Δ = 9408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9408}=\sqrt{3136*3}=\sqrt{3136}*\sqrt{3}=56\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56\sqrt{3}}{2*1}=\frac{0-56\sqrt{3}}{2}
=-\frac{56\sqrt{3}}{2}
=-28\sqrt{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56\sqrt{3}}{2*1}=\frac{0+56\sqrt{3}}{2}
=\frac{56\sqrt{3}}{2}
=28\sqrt{3}
$